Finding the overall uncertainty

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SUMMARY

The discussion focuses on calculating the overall uncertainty of the variable R, defined as R = (h² + l²) / 2h. The uncertainties provided are ±0.57% for h, ±1.14% for h², and ±7% for l². Participants clarify that the uncertainty in h² is derived from the uncertainty in h, specifically by multiplying the percentage uncertainty of h by 2. The conversation emphasizes the distinction between actual uncertainty and percentage uncertainty, highlighting the importance of using differential calculus to compute uncertainties accurately.

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Ch3m_
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Homework Statement


How do I find the overall uncertainty of R when R = (h2+l2)/2h

Homework Equations


uncertainty in h = ±0.57%
uncertainty in h2=±1.14%
uncertainty in l2=±7%

The Attempt at a Solution


√1.142+72+0.572
 
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Use the "differential"- R = (h2+l2)/2h dR= [(1- 2(h^2+ l^2))/h^2]dh+ (l/h)dl. Set dh and dl equal to the uncertainties in h and l respectively. You will need "current" values for h and l as well as for dh and dl. I do not understand you last values. Where you have "h = ±0.57%" do you mean the uncertainty in h (my "dh") rather than h itself? Also you have "h2=±1.14%" which is 2 times your h, not h squared.
 
HallsofIvy said:
Use the "differential"- R = (h2+l2)/2h dR= [(1- 2(h^2+ l^2))/h^2]dh+ (l/h)dl. Set dh and dl equal to the uncertainties in h and l respectively. You will need "current" values for h and l as well as for dh and dl. I do not understand you last values. Where you have "h = ±0.57%" do you mean the uncertainty in h (my "dh") rather than h itself? Also you have "h2=±1.14%" which is 2 times your h, not h squared.
<br /> <br /> Yeah those are the actual uncertainties in the values<br /> h = ±0.57% is the % uncertainty, where h is a measurement of length in m<br /> To get the uncertainty in h<sup>2</sup> you multiply the %uncertainty of h by 2 yeah?
 
Ch3m_ said:
Yeah those are the actual uncertainties in the values
h = ±0.57% is the % uncertainty, where h is a measurement of length in m
To get the uncertainty in h2 you multiply the %uncertainty of h by 2 yeah?
You are confusing me by saying "actual uncertainty" at one point and "% uncertainty" at another- those are NOT the same thing. If h= 10, say, and the "actual uncertainty" (I would say "relative error") is 0.5 then the "percentage uncertainty" is (0.5)/(10)= 0.05= 5%. If f(x)= x2 then df= 2x(dx) The "actual uncertainty in f is 2 times the value of f time the "actual uncertainty" in x. The "percent uncertainty" in f is df/f. Dividing both sides of the previous equation by f, df/f= 2x(dx)/f= 2x(dx)/x2= 2(dx/x) so the percent uncertainty in x2 is 2 times the percent uncertainty in x.

There is an engineer's "rule of thumb" that "when quantities are added their errors add and when quantities multiply their relative errors add".
 

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