Finding the possible values of a force pushing a block

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SUMMARY

The discussion focuses on determining the possible values of a force pushing a block, specifically analyzing the components of the applied force and the role of static friction. Key equations include the static friction formula μ = ffriction/fnormal and the relationship between vertical and horizontal force components. The importance of drawing a free body diagram is emphasized as a critical first step in visualizing the forces acting on the block. Participants highlight the necessity of understanding the normal reaction force and its interaction with applied forces to prevent slipping.

PREREQUISITES
  • Understanding of static friction and its calculation using μ = ffriction/fnormal
  • Knowledge of force components, specifically vertical and horizontal components
  • Ability to construct and interpret free body diagrams
  • Familiarity with Newton's laws of motion
NEXT STEPS
  • Study the principles of free body diagrams in physics
  • Learn about the calculation of normal and frictional forces in various scenarios
  • Explore the effects of varying applied forces on static friction
  • Investigate the relationship between force components and motion in inclined planes
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for effective methods to teach force interactions and static friction concepts.

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Homework Statement



35apxyx.jpg


Homework Equations



I believe the only necessary equations would be those utilized to find the X and Y components of a certain force as well as the formula used to find μs

µ = ffriction/fnormal

The Attempt at a Solution



Attempt:

I'm not really sure where to start. If someone could just give me a push in the right direction, it'd be much appreciated. :redface:
 
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AryRezvani said:

Homework Statement



35apxyx.jpg


Homework Equations



I believe the only necessary equations would be those utilized to find the X and Y components of a certain force as well as the formula used to find μs

µ = ffriction/fnormal

The Attempt at a Solution



Attempt:

I'm not really sure where to start. If someone could just give me a push in the right direction, it'd be much appreciated. :redface:

In all cases, the Normal Reaction Force [to be used in the Friction = μN] is the horizontal component of the applied Force, which they called P.

Also in all cases, the vertical forces acting on the block are: mg, down, Pvert, up plus friction.

If you push with too small a force, the block will slip down, so friction will act up. When the force becomes big enough to stop the slip, Pvert, up + friction, up will equal mg, down.

If you push too hard, the block will slip up, so friction will act down. At the point of slipping

Pvert, up will equal mg, down plus friction, down

Note: Pvert, up means the vertical component of the applied force P
 
The applied force P presses into the surface as well as along the surface.
Since the block has no acceleration into (or away from) the surface, there must be another force pointing away from the surface to oppose this.

Some people call this the "normal" force, and some the "reaction" force, at the surface.
PeterO has a slightly different picture - where the applied force is divided into normal and parallel components - which works just as well for this situation.

I'm not really sure where to start. If someone could just give me a push in the right direction, it'd be much appreciated.
The starting point is to draw a free body diagram.
It will have force arrows for weight (W), the applied force (P), and the normal/reaction (N) force and static friction (f).
[I like to give friction a lower-case "f", and I don't like subscripts.]
 

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