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How can I find the primitive of $\int_{\gamma}ze^{z^2}dz$ from $i$ to $2-i$?
dwsmith said:How can I find the primitive of $\int_{\gamma}ze^{z^2}dz$ from $i$ to $2-i$?
Ackbach said:$$\int z e^{z^{2}}\,dz=\frac{1}{2}\int 2z e^{z^{2}}\,dz.$$
Can you finish?
dwsmith said:So $\left(\frac{e^{z^2}}{2}\right)'=\int ze^{z^2}dz$ Then to solve the integral I just integrate g'(z) right?