Finding the pushing force needed to keep object from sliding down wall

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SUMMARY

The required pushing force to prevent a 2.88 kg book from sliding down a wall, given a coefficient of static friction of 0.322, is calculated to be 87.6 N. The calculation is based on the relationship between the normal force and the weight of the book, where the normal force equals the weight divided by the coefficient of static friction. The derived formula is F = mg/μs, leading to the conclusion that the pushing force must exceed the weight of the book due to the friction coefficient being less than 1.

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Timebomb3750
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This problem has been bugging me, seeing that my answer seems off. But who knows. Given the following measurements, find the required pushing force needed to keep a book from sliding down the wall.

Homework Statement


M= 2.88kg
Coefficient of static friction= .322

Homework Equations


Seeing that the book can't move, I figured that F=Normal force
mg=2.88kg(9.80 m/s^2)=28.2N
force of static friction=μsN

ƩFx=F-N=0
meaning F=N (Makes sense)

ƩFy=mg-fs=0
meaning mg=μs(N)
thus, N=(mg/μs)

The Attempt at a Solution


I did a simple substitution by setting F=(mg/μs)=(28.2N/.322)=87.6N

To me, that answer seems a little high. So, is my reasoning and/or answer correct?
 
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The answer must be greater in magnitude than the weight of the book because friction coefficient < 1. Your answer looks good to me.
 
LawrenceC said:
The answer must be greater in magnitude than the weight of the book because friction coefficient < 1. Your answer looks good to me.

That's good to know. Thanks.
 

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