Finding the Radius (word problem)

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SUMMARY

The forum discussion revolves around solving a trigonometric problem involving a pipe positioned between two blocks of different heights (1 inch and 2 inches) and an arc measuring 6 inches. Participants provided equations to determine the radius (r) of the arc, specifically: r cos(α) + 1 = r, r cos(β) + 2 = r, and r(α + β) = 6. The consensus is that the solution requires numerical methods, as there is no elementary solution available, and tools like Maple or a TI-89 calculator can be utilized for computation.

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  • #31
Miike012 said:
But yes that is the answer in the back of my trig book... How did you get that?
And I have a TI-89 calc..

I used Maple. With a program like that, there is little work to do. Here's the steps you type to solve it with Maple. I simplified it slightly for clarity:

> equation1 := r*cos(alpha)+1 = r;
> equation2 := r*cos(beta)+2 = r;
> equation3 := r*(alpha+beta) = 6;

> fsolve({equation1,equation2,equation3}, {r, alpha, beta});

{r = 2.768080732, alpha = 0.8779382494, beta = 1.289628589}

> alphadegrees := evalf(180*alpha/Pi); 50.30215635

> betadegrees := evalf(180*beta/Pi); 73.89027526

Takes all the pain and suffering out of it, eh?
 
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  • #32
I have another problem...

Six Identical pipes, each with radius of 1 foot are ties tightly together with a metal band... Find the length of the metal band...

I posted a picture...

My strategy is dividing the figure in half
Then finding the measure of the two arcs in red ( which should be equal)
Then finding the measure of the yellow line..
Once I find that... I can multiply it by three...
I am just not sure of how to do it...
 

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  • #33
erm :redface: … page 3 ? …

for a new problem, best to start a new thread :smile:
 
  • #34
okay
 

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