Finding the Shortest Ladder: Solving for the Optimal Angle

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The discussion focuses on determining the shortest ladder that can reach a wall while going over a fence. The equation derived for the ladder's length involves the angle x, expressed as (3√3 / sin x) + sec x. To find the optimal ladder length, the derivative of this equation should be taken with respect to x, set to zero, and solved for x. The height of the ladder is identified as 3√3, which plays a crucial role in calculating the ladder's length. The approach emphasizes calculus in optimizing the ladder's design.
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Finding the "shortest ladder"

Problem

I was given an analogy involving a ladder that goes over a fence and then leans against a wall a meter after the fence. The question wanted me to answer "what is the shortest ladder that goes over the fence and reaches the wall"

The Attempt at a Solution



I worked out the equation of the "ladder" (i.e line from the ground to the wall) is:

(3sqrt(3) / sin x) + sec x

(where x is the angle the ladder makes with the ground and the wall)

How can i work out the "shortest" ladder that can be made to reach the wall. Is is simply the derivative of the ladder?
 
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So 3sqrt(3) must be the height of the ladder h, right? Yes, the length of the ladder is L=h/sin(x)+1/cos(x). Differentiate that with respect to the angle, x, set it equal to zero and solve for x.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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