HELP calculus optimization problem: fitting thin rod through corridor

In summary: The first question is asking for the largest length, while the second question is asking for the shortest length. This is because the max length is the same as the shortest length if you only consider the local maxima of the function. If you consider the local minima, the max length is going to be longer than the shortest length.
  • #1
sickle
12
0
I am having trouble conceptualizing a calculus optimization problem.
I can find the answer to the problem by using the procedure but i am quite uncertain of how the equations match up with what's actually going on in the situation!

Problem: What is the max length of widthless rigid pole that can be carried around a corner of two corridors of width a and b meeting at a right angle?

The solution is identical to finding the shortest length of a ladder from the ground to a wall if there's a block in front and blocking the wall.
This 2nd Q. makes sense because we are minimizing the length of the ladder and indeed the math spits out a local min value.

Now why is it that the conditions to finding the longest length is identical to find the shortest ladder??
 
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  • #2
they are solve for either the local maxima, or local minima of a function, both of which correspond to f'(x)=0, so the solution method is the same.

You could use the 2nd derivative method to check whether it is a max or min, though it is often obvious based on the problem framing
 
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  • #3
It's because the problems are physically very similar. As you turn around the corner, you want to find a ladder which touches both walls only once (if it touches both walls for an extended period of time, then it really passed through the walls at some point and that's not allowed). If you think about the corner you are trying to navigate as the block and the outside walls of the corner as the wall and floor, you're looking for a ladder which is only capable of touching the floor and wall in one position, not many positions. This is going to be the shortest ladder capable of touching the wall and the floor at the same time.

The more pertinent question though, is why do you think the second question makes sense because it's asking for a minimum, and the first question doesn't because it's asking for a maximum?
 

1. How do you approach a calculus optimization problem?

To approach a calculus optimization problem, you first need to identify the objective function and the constraints. Then, find the derivative of the objective function and set it equal to zero to find critical points. Finally, evaluate the critical points to determine the maximum or minimum value.

2. What is the objective function in a fitting thin rod through a corridor problem?

The objective function in this problem is the length of the rod. The goal is to minimize the length of the rod so that it can fit through the corridor.

3. How do you set up the constraints in this optimization problem?

The constraints in this problem are the dimensions of the corridor. You will need to use the Pythagorean theorem to set up the constraints as equations and then use those equations to eliminate one variable. This will leave you with a single-variable function that you can optimize.

4. Can you use both the first and second derivative tests in this problem?

Yes, you can use both the first and second derivative tests to determine if the critical points found are maximum or minimum values. The first derivative test tells you if the critical point is a local maximum or minimum, and the second derivative test confirms if it is a maximum or minimum.

5. Are there any real-world applications for this type of calculus optimization problem?

Yes, this type of optimization problem can be applied in various fields, such as engineering, physics, and economics. For example, it can be used to determine the most efficient design for a bridge or to minimize the cost of producing a certain product.

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