Finding the Shortest Path in a Vector Space

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SUMMARY

The discussion focuses on calculating the shortest path a fly can take in a room with dimensions 2.95 m (height), 4.68 m (width), and 6.19 m (length). The magnitude of the fly's displacement is determined using the formula SQ RT √(2.95² + (x)²), where x is calculated as SQ RT of √(4.68² + 6.19²), resulting in a displacement of 8.30 m. For the shortest walking path, the formula SQ RT √((w+h)² + (l)²) is used, but participants express confusion regarding the identification of width and length.

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Homework Statement



A room has dimensions 2.95 m (height) × 4.68 m × 6.19 m. A fly starting at one corner flies around, ending up at the diagonally opposite corner. (a) What is the magnitude of its displacement? (b) If the fly walks rather than flies, what is the length of the shortest path it can take?


2. Relevant topic
Vectors


The Attempt at a Solution


SQ RT √(2.952+ (x)2); x = SQ RT of √(4.682 + 6.192)
= 8.30

Part B, I have problems with as I do not know which one is width/length : (

The answer is
SQ RT
√((w+h)2 + (l)2)
But because I do not know which is which I have a slight dilemma... Is there a way to tell?
 
Physics news on Phys.org
Shorter distance is width.
 
rl.bhat said:
Shorter distance is width.

Thank you very much.
 

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