Finding the Slope of Tangent Line for Polar Curves

[Justabeginner]

Homework Statement

Calculate a function of theta that gives the slope of the tangent line (dy/dx) to the polar curve r at some angle theta.

Homework Equations

dy/dx= f'(theta)sin(theta) + f(theta)cos(theta)/[f'(theta)cos(theta) - f(theta) sin(theta)]

The Attempt at a Solution

I am not even understanding what the question is asking. All I know is the formula above. Can someone please help me out? Thank you.

 

[voko]

That formula is the answer unless you are given some particular equation for the curve.

 

[Justabeginner]

Oh, okay. So they are just asking for me to prove how I got to that using the x= r cos theta, y= r sin theta, and dy/dx= dy/dtheta / dx/dtheta formulas. Thank you!