Finding the Solution for x in a Fractional Equation

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Homework Help Overview

The problem involves solving a fractional equation of the form x/m - 1/n = 3x/mn for the variable x. Participants are discussing the steps needed to isolate x and simplify the equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to manipulate the equation to isolate x, with some suggesting the need to factor out x and rearrange terms. Questions arise about the process of multiplying through by mn and how to handle fractions in the equation.

Discussion Status

Some participants have provided guidance on how to rearrange the equation and factor out x. There is an ongoing exploration of the mathematical rules involved in manipulating fractions and finding a common denominator. Multiple interpretations of the steps are being discussed.

Contextual Notes

Participants express confusion regarding the handling of fractions and the need for a common denominator when subtracting them. There is also mention of a specific final answer that one participant is trying to achieve, which may not align with the current understanding of the problem.

Amaz1ng
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Homework Statement


Hello I have this problem here:x/m - 1/n = 3x/mn. Solve for x.

Homework Equations


The Attempt at a Solution



I got it to this level:

xn = 3x + m

and the final answer is m / n - 3.

How do I go about getting the final answer? I just want to know what I'm missing because I don't see how to reduce it to the final answer. I always have these problems with fractions and division.
 
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What you want to do is to be able to factor out x. In such questions, we usually seek to reduce the equation to a form ax = b, where a and b are independent of x.
To do that, we clearly need all the terms containing x on one side to be able to factor it out. Please carry on :)
 
[itex]\frac{x}{m}\,-\,\frac{1}{n}\,=\,\frac{3x}{mn}[/itex]

When someone says to multiply through by mn, what mathematics rule is that and how do you go about doing it?

Supposedly, multiplying through my mn gives:

[itex]xn\,-\,m\,=\,3x[/itex]

but I don't see how.
 
Rewrite your equation as:
[tex]xn - 3x = m[/tex]
[tex]x (n-3) = m[/tex]
Do you see it now? The key idea is to bring all the 'x' terms on one side so you can factor it out.
 
I get these parts:

[itex] xn\,-\,m\,=\,3x[/itex]

[tex] x (n-3) = m[/tex]

But how do you get it from here to here:

[itex] \frac{x}{m}\,-\,\frac{1}{n}\,=\,\frac{3x}{mn}[/itex]

to here:

[itex] xn\,-\,m\,=\,3x[/itex]
 
Ok the issue is that I'm thinking about it like this:

if you subtract two fractions then you have to find the LCM or some common denominator. How do you do that with this or am I thinking about it wrong?

mn * x/m - mn * 1/n

What do you do with this? ;o
 
Amaz1ng said:
Ok the issue is that I'm thinking about it like this:

if you subtract two fractions then you have to find the LCM or some common denominator. How do you do that with this or am I thinking about it wrong?

mn * x/m - mn * 1/n

What do you do with this? ;o

The first term is m times n, times x, divided by m. m divided by m is 1, so it reduces to nx for the same reason that 2*3/2 = 3.
 
Ok I think I got it...I was thinking about it like a fraction.

Thanks a lot. :D
 

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