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"A ball of mass .500kg is rolling across a table top with a speed of 5.00 m/s. When the ball reaches the edge of the table, it rolls down a frictionless incline onto the floor 1.00 meter below (without bouncing). What is the speed of the ball when it reaches the floor (just before it touches the floor)?"

I use the equation PEf + KEf = PEi + KEi and then get KEf = PEi, which then leads to

.5mv^2 = mgh

From here, I'm stuck. Since the ramp is frictionless, does the ball accelerate the same as it would if it was dropped? And, how would I add in the initial speed of 5.00 m/s?