Finding the square with a fraction in the expression

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Amaz1ng
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Homework Statement



[tex]x^2 + x + \frac{1}{4}[/tex]

Homework Equations



This should be written in the form:

[tex](x+y)^2[/tex]

Just to add a bit more info, the exercise is to "Write each of the following as the square of a binomial expression". So basically the book teachs to take the rook of x^2 and 1/2, multiply those together, then multiply by 2. If that is equal to the middle term, then you can write:

[tex](\sqrt{x^2} + \sqrt{1/4})^2[/tex]

The Attempt at a Solution



My answer is that this can't be written as a square...which is what the textbook is asking to do. Anyway, I don't think this can be written as a square
 
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Hi Amaz1ng.

You are asked to find if there is a value a so you can write

[tex]x^{2}+x+1/4=(x+a)^{2}[/tex]
 
Karlx said:
Hi Amaz1ng.

You are asked to find if there is a value a so you can write

[tex]x^{2}+x+1/4=(x+a)^{2}[/tex]
I don't believe there is such a value of a. You can, however write x2 + x + 1/4 as (x + a)2 + b.

This technique is called completing the square. Your textbook should have numerous examples of how to do this.
 
Just to add a bit more info, the exercise is to "Write each of the following as the square of a binomial expression".
 
Karlx said:
Hi Amaz1ng.

You are asked to find if there is a value a so you can write

[tex]x^{2}+x+1/4=(x+a)^{2}[/tex]

Mark44 said:
I don't believe there is such a value of a.

Yes there is.

Using the perfect square trinomial pattern
[tex]a^2 + 2ab + b^2 = (a + b)^2[/tex]
equate
[tex]x^{2} + x + \frac{1}{4}[/tex]
with the left side to find a and b. If x corresponds to a, what corresponds to b?
 
answer in book.. :wink:

[tex](x+\frac{1}{2})^2[/tex]

..it's squared but for some reason the square doesn't show.
 
eumyang said:
Yes there is.
I don't know why I didn't see that.:blushing:
eumyang said:
Using the perfect square trinomial pattern
[tex]a^2 + 2ab + b^2 = (a + b)^2[/tex]
equate
[tex]x^{2} + x + \frac{1}{4}[/tex]
with the left side to find a and b. If x corresponds to a, what corresponds to b?