Finding the sum of a geometric series

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The discussion focuses on finding the sum of a geometric series, specifically the ratio (r) and the confusion surrounding the variable n. The ratio is established as 10, derived from the general term 5x10^i, which indicates that the ratio of consecutive terms is based on the index number. The formula for the sum of a geometric series is provided, highlighting the relationship between the first term, the ratio, and n. Clarification is sought on how the expression 1-r becomes reversed in the solution, with a suggestion to multiply the numerator and denominator by -1 for better understanding. Wolfram Mathematica is recommended for further explanation on geometric series.
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Homework Statement
Calculate:
Relevant Equations
The sum of 5 x 10^i, from i=0 to i=n-1
I'm using the sum of a geometric series formula, but I'm not sure how to find the ratio, r. The n is confusing me.

The solution is below, but I'm having trouble with the penultimate step.

Screenshot 2019-10-20 11.31.30.png
 
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The ratio is 10. In a geometric seqence the ratio of consecutive terms is always the item that is raised to the power of the sequence index number (j in this case).
 
Here r is the ratio of consecutive terms. The general term is 5x10^i ; it is indexed by i. Can you use this to find the ratio between consecutive terms?
 
Consider this:
##\sum_{i=0}^{n-1} ab^i = \sum_{i=0}^\infty ab^i - \sum_{i=n}^\infty ab^i##
 
andrewkirk said:
The ratio is 10. In a geometric seqence the ratio of consecutive terms is always the item that is raised to the power of the sequence index number (j in this case).
Thanks. The formula is first term*(1-r^n)/(1-r). How does 1-r become reversed in the solution?
 
Try multiplying the top and bottom of the expression by -1.
 
Wolfram

Wolfram Mathmatica gives a nice explanation of geometric series.
 

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