An energetic father stands at the summit of a conical hill as he spins his 25kg child around on a 5.7kg cart with a 2.4m long rope. The sides of the hill are inclined at 22º. He keeps the rope parallel to the ground, and friction is negligible. What rope tension will allow the cart to spin with the 17 ? I tried working this problem backwards, from another example in my physics book but the answer came out wrong. First, I converted 17 rpm to 1.780235837 rad/s. Then, I plugged that value into omega=(v/r) and got 4.272566009 m/s. After that I used the equation T=mv^(2)/r and came up with 233.5095763 N, which I rounded to 230 N. Help?