Father and Child Cart Spin: Calculating Rope Tension

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SUMMARY

The discussion focuses on calculating the rope tension required for a father to spin his 24 kg child on a 5.7 kg cart using a 2.0-meter-long rope at 17 RPM on a conical hill with a 24-degree incline. The tension formula T = mv²/R is utilized, with the velocity calculated as 3.6 m/s after converting RPM to radians per second. Participants emphasize the need to analyze both horizontal and vertical components of tension and apply Newton's second law to derive the correct tension value.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Familiarity with Newton's second law of motion
  • Knowledge of converting RPM to radians per second
  • Basic principles of forces acting on inclined planes
NEXT STEPS
  • Study the derivation of tension in circular motion scenarios
  • Learn about the effects of incline angles on tension calculations
  • Explore advanced applications of Newton's second law in rotational dynamics
  • Investigate the relationship between angular velocity and linear velocity in circular motion
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of circular motion and tension calculations in inclined scenarios.

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An energetic father stands at the summit of a conical hill as he spins his 24 kg child around on a 5.7 kg cart with a 2.0-m-long rope. The sides of the hill are inclined at 24 degrees . He keeps the rope parallel to the ground, and friction is negligible
What rope tension will allow the cart to spin with the 17 rpm?

I know the equation for tension is T= mv^2/R

I tried to convert 17 rpms into rad/s and got 1.8 rad/s I got the velocity as 3.6 m/s. I don't know if I did this right but any feedback or corrections would be greatly appreciated.. Thanks!
 
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You need to split up your tension into horizontal and vertical components. What forces are acting in the horizontal direction, the vertical? Then you can use Newton's second law to solve for the tension.
 

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