1. The problem statement, all variables and given/known data Assume the three blocks (m1 = 1.0 kg, m2 = 2.0 kg, and m3 = 2.5 kg) portrayed in the figure below move on a frictionless surface and a force F = 48 N acts as shown on the 2.5-kg block. Click link for image: http://www.webassign.net/sercp9/4-p-029a-mi.gif (a) Determine the acceleration given this system. (b) Determine the tension in the cord connecting the 2.5-kg and the 1.0-kg blocks. and (c) Determine the force exerted by the 1.0-kg block on the 2.0-kg block. 2. Relevant equations ƩF = ma F-T = ma 3. The attempt at a solution a) 48N = ma a = 48/5.5 <----- sum of all masses a = 8.73 m/s^2 (which was correct). b) I made two FBD's, one with the mass of 1kg and another with 2.5kg. for the first mass: T=ma for the second mass: F-T = ma substitute first equation into this one: 48-(ma)= ma 48= 2(ma) a = 24/3.5 <--- 3.5 was the sum of the two masses a = 6.857 m/s^2 Then substitute the new value of a into the first equation: T = 3.5(6.875) T = 24 N (This was wrong) c) ƩF= ma F= 1kg(8.73) <------- this acceleration was found at the beginning, and was correct F = 8.72N (which was wrong) Your help would be really appreciated guys.