# What is the tension in the right cable?

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1. Mar 12, 2015

1. The problem statement, all variables and given/known data
2 cables are used to support a 24kg mass on a 1.6m long, 8kg uniform horizontal beam. The 24kg mass is 0.6m from the right cable. What is the tension in the right cable?

2. Relevant equations
torque = rFsinx

3. The attempt at a solution

Fy = ma = 24(9.8) = 235.2N
Fx = ?
resultant F - ?

2. Mar 12, 2015

### billy_joule

There is no Fx forces acting if I'm visualizing it correctly.A picture would help.
Take moments about the left end, solve for the one unknown force - the rhs cable tension.

3. Mar 12, 2015

### Brian T

Is the object moving? If so or if not, what does this tell you about the net force.

4. Mar 12, 2015

### BvU

And are the cables vertical? Where are they attached to the beam? At the ends ?

5. Mar 12, 2015

### haruspex

There is some confused thinking here:
Fy = ma should be $\Sigma F_y = ma_y$, i.e. the net force in the Y direction gives rise to an acceleration in the Y direction.
It is not clear whether you are considering forces on the beam, forces on the mass, or forces on the two as a system. Whichever, 24(9.8) is only one force in the Y direction, not the net force.
I assume the cables are vertical and attached to the ends of the beam. If so, follow billy_joule's advice. You can get the answer without using $\Sigma F_y = ma_y$.