A horse race takes place on a long straight track, at the beginning of the race the horse accelerates from rest to some top speed with a (constant) acceleration of 1.13 m/s^2 and then maintains that top speed to the end of the race. The total time taken from the start of the race to its end is 2.05 minutes and the total distance covered is 2.41 km.
(a) What was the time elapsed during the acceleration phase of the horse's motion?
(b) What distance did the force cover during the acceleration phase of its motion?
(c)What was the top speed reached by the horse?
The Attempt at a Solution
a= 1.13 m/s^2
distance/displacement = 2410 m
V2^2 = V1^2+2ad
V2^2 = 0+2(1.13)(2410)
v2 = 73.8 m/s
v2 = v1+at
Therefore, t = v2-v1/a
t = (73.8-0)/(1.13) = 65.3 s
d = v2^2-v1^2/2a
d= (73.8)-(0)/2(1.13) = 2130 m
(C) Top speed was found in (A) to be 73.8 m/s
This was my guess on how to do it...help?