Finding the time evolution of a state

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SUMMARY

The discussion focuses on calculating the time evolution of a quantum state using the Hamiltonian \( H = \alpha (B_x S_x + B_y S_y + B_z S_z) \) and the initial condition \( \psi(0) = \begin{pmatrix} 1 \\ 0 \end{pmatrix} \). The eigenvalues derived are \( \lambda_1 = \frac{\alpha \hbar B_x}{2} \) and \( \lambda_2 = -\frac{\alpha \hbar B_x}{2} \), with corresponding eigenstates \( \begin{pmatrix} 1 \\ 1 \end{pmatrix} \) and \( \begin{pmatrix} 1 \\ -1 \end{pmatrix} \). The time evolution operator \( U(t) = \exp\left(-\frac{i H t}{\hbar}\right) \) is applied, leading to the expression \( \psi(t) = A \exp\left(-\frac{i \alpha B_x t}{2}\right) \begin{pmatrix} 1 \\ 1 \end{pmatrix} + B \exp\left(\frac{i \alpha B_x t}{2}\right) \begin{pmatrix} 1 \\ -1 \end{pmatrix} \), with normalization constants \( A \) and \( B \) to be determined.

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Kyrios
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Homework Statement



1) Using energies and eigenstates that I've worked out, find time evolution ψ(t) of a state that has an initial condition ψ(0) = <br /> \begin{pmatrix}<br /> 1 \\<br /> 0\\<br /> \end{pmatrix}<br />

2) Find the expectation values < Sy> and <Sz> as a function of time.


Homework Equations



The Hamiltonian is H = \alpha (B_x S_x + B_y S_y + B_z S_z)


The energies that I worked out were the eigenvalues:

\lambda_1= \frac{ \alpha \hbar B_x }{2}

\lambda_2= - \frac{ \alpha \hbar B_x }{2}


The eigenstates were the eigenvectors
<br /> \begin{pmatrix}<br /> 1 \\<br /> 1\\<br /> \end{pmatrix}<br />

and

<br /> \begin{pmatrix}<br /> 1 \\<br /> -1\\<br /> \end{pmatrix}<br />

The Attempt at a Solution



I tried using the time evolution operator
U(t)= exp( \frac{ -i H t}{\hbar} )

I ended up with something that looks like this:

\psi(t) = A exp( \frac{ -i \alpha B_x t}{2} ) (1, 1) + B exp( \frac{ i \alpha B_x t}{2} ) (1, -1)


But I'm really unsure of where to go from here, or whether this is even right.
 
Last edited:
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Just check if your answer satisfies the inital condition and determine the constants A and B from normalization.
 

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