1. The problem statement, all variables and given/known data We are given a cubic tank, with a parabolic object y = x^2 (one end is -1, 1 and the other is 1, 1 --> it only goes up to 1). The total pressure it can withstand is 160 lbs. Also, the fluid density is 50 lbs. Find: a) Total pressure if water is 2-feet deep. b) Max height the tank can be filled. 2. Relevant equations Fluid density is 50 lbs. Total pressure that can be withstood by the object: 160 lbs 3. The attempt at a solution I think I got most of this: For part "a," I'm getting a pressure of 50 (2-y), and for the area of the object, I'm getting 2 root(y) dy. Thus, I got the integral, from 0 to 1, of 100 (2-y)(root(y)), and then got: 100 [4y^(3/2) / 3 - 2y^(5/2) / 5], from 0 to 1, and the answer I got was about 93.33 lbs of total pressure. For part "b," I'm a little confused as to how to solve it. I set 160 equal to the line above, and then just divide both sides by 100... Then, since the powers are negligible with limits of integration of 0 and 1, I get 1.6 = 4y/3 - 2y/5 --> 1.6 = 14y/15 ---> y = 1.7143, and that's definitely not the answer I'm looking for.