Finding the transformation of a matrix

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I see, I didn't know that.
I guess I understand. I'll practice to make sure I understand properly.
Thank you
 
on Phys.org
Redwaves said:
From that, the transformation seems to be an rotation of ##\phi - \theta## clockwise and then a reflection over the x axis. Is this correct?
Yes, you are correct. It can be represented by
##
\begin{pmatrix}
\cos(\theta) & \sin(\theta) \\
\sin(\theta) & -\cos(\theta)
\end{pmatrix}
=
\begin{pmatrix}
1 & 0 \\
0 & -1
\end{pmatrix}

\begin{pmatrix}
\cos(-\theta) & -\sin(-\theta) \\
\sin(-\theta) & \cos(-\theta)
\end{pmatrix}
##
That is a rotation of angle ##\theta## in the clockwise direction followed by a reflection across the X-axis.