Finding the undamped natural frequency of 2nd order system

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SUMMARY

The discussion focuses on finding the undamped natural frequency and damping ratio of a second-order system represented by the differential equation 2y'' + 4y' + 8y = 8x. The damping ratio (z) is calculated as 0.5, while the undamped natural frequency (ω) is determined to be 2.0. Confusion arises regarding the correct value of ω, with some participants suggesting it could be 0.1 or 1.73 based on different interpretations. The auxiliary equation 2m² + 4m + 8 = 0 is solved using the quadratic formula, leading to a general solution that confirms the undamped frequency as 2.0.

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  • Understanding of second-order differential equations
  • Familiarity with damping ratio and natural frequency concepts
  • Knowledge of the quadratic formula for solving polynomial equations
  • Basic principles of Laplace transforms in system dynamics
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engnrshyckh
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the following 2nd order differential equation is given:
2y'' + 4y' +8y=8x........(1)
i want to find damping ratio, undamped natural frequency, damping ratio coefficient and time constant for the above system.
solution:
comparimg (1) with general system equaion

SysDyn2A1.gif

(veriable can be exchanged)
{where: x(t) = Response of the System,
u(t) = Input to the System,
z = Damping Ratio,
wn=Undamped Natural Frequency,
Gdc= The DC Gain of the System.}
damping ratio z or zeta:

2zw=2
w=2 so z=2/4=0.5

undamped natural frequency w or omega:
w=2 but correct ans is 1. any help?
 
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Using: http://en.wikipedia.org/wiki/Harmonic_oscillator

Putting the DE familiar form: ##\ddot x + 2\dot x + 4x = 4t## would be the equivalent right?
Compare with ##\ddot x + 2\zeta \omega_0 \dot x + \omega_0^2 x = f(t)## I get ##2\zeta\omega =2## like you did, and ##\omega_0^2=4\implies \omega_0=2 \implies \zeta = 1/2## ...

Are you sure the answer you quote as "w" is the undamped frequency?

 
Simon Bridge said:
Using: http://en.wikipedia.org/wiki/Harmonic_oscillator

Putting the DE familiar form: ##\ddot x + 2\dot x + 4x = 4t## would be the equivalent right?
Compare with ##\ddot x + 2\zeta \omega_0 \dot x + \omega_0^2 x = f(t)## I get ##2\zeta\omega =2## like you did, and ##\omega_0^2=4\implies \omega_0=2 \implies \zeta = 1/2## ...

Are you sure the answer you quote as "w" is the undamped frequency?
http://www.facstaff.bucknell.edu/mastascu/eControlHTML/SysDyn/SysDyn2.html yes it is undamped natural frequency
 
engnrshyckh said:
the following 2nd order differential equation is given:
2y'' + 4y' +8y=8x........(1)
i want to find damping ratio, undamped natural frequency, damping ratio coefficient and time constant for the above system.
solution:
comparimg (1) with general system equaion

SysDyn2A1.gif

(veriable can be exchanged)
{where: x(t) = Response of the System,
u(t) = Input to the System,
z = Damping Ratio,
wn=Undamped Natural Frequency,
Gdc= The DC Gain of the System.}
damping ratio z or zeta:

2zw=2
w=2 so z=2/4=0.5

undamped natural frequency w or omega:
w=2 but correct ans is 0.1. any help?
 
another way is to use laplace transformation as:

SysDyn2A1.gif


  • Then, Laplace transforming both sides and solving for the transfer function - the ratio of the transform of the output to the transform of the input, we find the transfer function to be.
SysDyn2A2.gif

but you still get wn=2
 
I agree the undamped w = 2
Why do you think the correct answer is .1?
Taking damping into consideration w = 1.73
 
Tom_K said:
I agree the undamped w = 2
Why do you think the correct answer is .1?
Taking damping into consideration w = 1.73
please tell me how you find w=1.73...
w=0.1 ans is given in book Electronics and communication engg (OT) by Handa
 
engnrshyckh said:
please tell me how you find w=1.73...
w=0.1 ans is given in book Electronics and communication engg (OT) by Handa

The auxiliary equation is: 2m^2 + 4m + 8 = 0
Use the quadratic formula to solve for the roots = -1 +/- i 1.73
That leads to the general solution form of e^-t*(A Cos 1.73t + B Sin 1.73t)
A damped oscillation where w = 1.73
To solve for the undamped case just disregard the coefficient of the m term which represents the damping resistance. The roots then are +/- i 2 purely imaginary
An undamped oscillation where w = 2.0

I don't know where that 0.1 could have come from, a typo maybe?
 
Tom_K said:
The auxiliary equation is: 2m^2 + 4m + 8 = 0
Use the quadratic formula to solve for the roots = -1 +/- i 1.73
That leads to the general solution form of e^-t*(A Cos 1.73t + B Sin 1.73t)
A damped oscillation where w = 1.73
To solve for the undamped case just disregard the coefficient of the m term which represents the damping resistance. The roots then are +/- i 2 purely imaginary
An undamped oscillation where w = 2.0

I don't know where that 0.1 could have come from, a typo maybe?
ty for the help. can you please tell me about damping co-efficient and time for this particular question?
 
  • #10
ty for the help. can you please tell me about damping co-efficient and time for this particular question?
... please show how you have attempted to answer the rest of the problem, then we can help you with it.
 
  • #11
Zeta=a/2w which implies that a=2 by letting w=2 and zeta=0.5 time constant is 1/a which is 0.5. I don't know about damping coefficient and hope u will help me out
 

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