Finding the value of this load resistor

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The discussion focuses on calculating the value of a load resistor in a series circuit setup. The voltage across the output is 4000V when open, dropping to 3000V when connected to the load resistor, indicating a voltage drop of 1000V across the internal resistance. The current calculated through the circuit is approximately 4.17 x 10^-5 Amps, which is also the current through the load resistor. Using the formula R = V/I, the resistance of the load resistor is determined to be 72 Mega ohms. The participant expresses confidence in their calculations but seeks reassurance to avoid potential mistakes.
Bolter
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Homework Statement
Calculate the resistance of load resistor
Relevant Equations
V = IR
Question:

Screenshot 2020-02-14 at 09.05.33.png


I first knew that this would be a series circuit setup, there the current all around the circuit would be the same.

It's given that when it's a open circuit, p.d. across the output is 4000V hence the emf is therefore 4000V. When it gets connected to a load resistor, the voltage share is 3000V thus the voltage share on the internal resistance of the voltage supply must be 1000V

From this I can work out the current flowing through the circuit which gave me 4.1666... x10^-5 Amps

This should mean that 4.1666... x10^-5 amps is also passing through the load resistor, so the resistance of the load resistor is R = V/I or 72 Mega ohms

IMG-3860.JPG


Any help would be really appreciated. Thanks!
 
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No help possible, except to convince you you are doing OK...
 
BvU said:
No help possible, except to convince you you are doing OK...

Ok thanks, I’m sure I am doing it right. It’s just that sometimes I make silly mistakes that I don’t tend to see at all but others can. But I checked again just to be sure
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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