Finding the Vertical Tangent Line of x3 + xy - y2 = 10 Curve

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SUMMARY

The curve defined by the equation x³ + xy - y² = 10 has a vertical tangent line when the first derivative dy/dx is undefined. The derivative is given by dy/dx = (-3x² - x)/(x - 2y). To find the vertical tangent line, one must set the denominator (x - 2y) equal to zero and solve for x and y. This approach correctly identifies the conditions under which the tangent line is vertical, contrasting with the incorrect method of setting x = 0, which yields a horizontal tangent.

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  • Understanding of implicit differentiation
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  • Familiarity with the concept of vertical and horizontal tangents
  • Basic algebra skills for solving equations
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  • Learn how to identify vertical and horizontal tangents in curves
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sonofjohn
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The curve defined by x3 +xy - y2 = 10 has a vertical tangent line when x = ?

To find when the tangent line is vertical, could I find when the slope is undefined for the original function? The way I previously tried this problem was by taking the first derivative and then finding when x = 0. That is one of the multiple choice answers but that cannot be right, for that would find the horizontal tangent and not the vertical tangent line.
 
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Now that I think about it couldn't I find where the slope is undefined by finding where the first derivative is undefined?

If I have

dy/dx = (-3x^2 - x)/(x-2y)

could I set the denominator = 0 and solve?
 
Yes, of course. I was wondering why you were setting "x= 0" before.
 

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