Finding the Volume Under a Surface Above a Triangle

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SUMMARY

The discussion focuses on calculating the volume under the surface defined by the equation z = y * x², above the triangular region with vertices at (4,0), (1,0), and (2,1). The user established the limits of integration as y = 0 to y = 1 and x = y + 1 to x = 4 - 2y, with the integrand being (y)(x)² dx dy. This setup is confirmed as correct by another participant, Mark, indicating that the limits and integrand are appropriate for solving the problem.

PREREQUISITES
  • Understanding of double integrals in calculus
  • Familiarity with the concept of volume under a surface
  • Knowledge of triangular regions in the Cartesian plane
  • Ability to perform integration with respect to multiple variables
NEXT STEPS
  • Study the application of double integrals for calculating volumes
  • Learn about setting up limits of integration for non-rectangular regions
  • Explore the use of Jacobians in changing variables for integration
  • Practice problems involving volume calculations under various surfaces
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Students in calculus courses, educators teaching integration techniques, and anyone interested in applying double integrals to solve volume problems in multivariable calculus.

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Homework Statement


find the volume under the surface z=(y)(x)^2 and above the triangle with vertices (4,0) (1,0) (2,1)



Homework Equations





The Attempt at a Solution



i got my limits of integration to be y=0 to y=1 and x=y+1 to x=4-2y. my integrand itself is (y)(x)^2dxdy

i just wanted to see if this is correct.
thanks!
 
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help please!
 
nobody ?
 
Mark44 said:
That should work.

^^^ thanks mark
 

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