Finding the x-component of a force using Coulomb's Law

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SUMMARY

The discussion focuses on calculating the x-component of the force between two point charges using Coulomb's Law. The initial force exerted by charge q1 (-2.9 μC) on charge q2 (5 μC) was determined to be -17.64 N. After displacing q2 by 2.4 cm in the positive y-direction, the new force was calculated to be -16.37 N, but the x-component was incorrectly derived as -11.58 N due to an assumption of a 45-degree angle. The correct approach involves accurately determining the angle based on the new positions of the charges.

PREREQUISITES
  • Coulomb's Law (F = k (q1q2)/(r^2))
  • Pythagorean theorem for distance calculation
  • Trigonometric functions (specifically cosine)
  • Understanding of electric charge units (microcoulombs)
NEXT STEPS
  • Review the derivation of Coulomb's Law and its applications
  • Learn how to calculate forces in two dimensions using vector components
  • Study the implications of charge displacement on force calculations
  • Explore trigonometric functions in physics, particularly in force resolution
USEFUL FOR

Students studying electrostatics, physics educators, and anyone involved in solving problems related to electric forces and charge interactions.

cherrymilk
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Homework Statement


(1) A point charge q1 = -2.9 μC is located at the origin of a co-ordinate system. Another point charge q2 = 5 μC is located along the x-axis at a distance x2 = 8.6 cm from q1.

The answer to this was -17.64N.

(2) Charge q2 is now displaced a distance y2 = 2.4 cm in the positive y-direction. What is the new value for the x-component of the force that q1 exerts on q2?

Homework Equations


Coulomb's Law: F = k (q1q2)/(r^2)


The Attempt at a Solution


Seeing that q2's position had changed, I calculated the new force exerted using Coulomb's Law. I used 9*10^9 for k, and using the Pythagorean theorem, I calculated the new distance between the charges, which I got to be 0.089. After using Coulomb's Law, I got an answer of -16.37N. To find the x-component, I multiplied this value by cos(45), giving me a final answer of -11.58. This, however, is apparently incorrect and I'm confused as to why.

Any help would be appreciated!
 
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Why did you chose 45 degrees as the angle?
 
OtherWindow said:
Why did you chose 45 degrees as the angle?

Ah, I see what I did wrong. I just assumed that because they had drawn the line they way they did in the figure, the angle was 45 degrees. Silly mistake, thanks for that!
 

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