Finding the X-intercept of a function

  • Thread starter Thread starter Airp
  • Start date Start date
  • Tags Tags
    Function
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
Airp
Messages
23
Reaction score
0

Homework Statement


F(x)= x-12x1/3 Find the X-intercept

Homework Equations


X-intercept means y=0

The Attempt at a Solution


My math teacher gave plus or minus 24sqrt3 as an answer, but I have no idea how he got that! He also got 0, but I do understand that one... I just don't know how to get the 24sqrt3 Could someone help me, please?
 
Physics news on Phys.org
Airp said:

Homework Statement


F(x)= x-12x1/3 Find the X-intercept

Homework Equations


X-intercept means y=0

The Attempt at a Solution


My math teacher gave plus or minus 24sqrt3 as an answer, but I have no idea how he got that! He also got 0, but I do understand that one... I just don't know how to get the 24sqrt3 Could someone help me, please?

Set ##u = x^{1/3}##, so your equation becomes ##0 = u^3 - 12 u##, or ##0 = u(u^2-12)##.
 
  • Like
Likes   Reactions: Airp
Thank You! Quick question: since you put everything to the cube, should you put -12 also to the power three, because that's how I finally got the answer! Thank you so much!
 
The u-substitution is all you need. However, the answer you get is for u. x = u^3. So you will cube your answer.
There should be no reason to cube 12. That would be assuming that
##F(x)^3=(x-12x^{1/3})^3 = x^3 - 12^3 x## but that is not how powers of polynomials work.
Edit:
However, in this case, since you are assuming that F(x) = 0 (x- intercept), you will get the right solution since:
##0=x-12x^{1/3}##
##x=12x^{1/3}##
##x^3=12^3x##
##0=x^3-12^3x##
There are many ways to get to the answer...just be sure you know why you are doing things.
 
Last edited:
  • Like
Likes   Reactions: Airp
RUber said:
The u-substitution is all you need. However, the answer you get is for u. x = u^3. So you will cube your answer.
There should be no reason to cube 12. That would be assuming that
##F(x)^3=(x-12x^{1/3})^3 = x^3 - 12^3 x## but that is not how powers of polynomials work.
Edit:
However, in this case, since you are assuming that F(x) = 0 (x- intercept), you will get the right solution since:
##0=x-12x^{1/3}##
##x=12x^{1/3}##
##x^3=12^3x##
##0=x^3-12^3x##
There are many ways to get to the answer...just be sure you know why you are doing things.
Thank you so much! This community really is awesome!