Finding time and distance with NLM.

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    Physics 11 Time
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Homework Help Overview

The problem involves a puck sliding across rough ice, experiencing friction, and requires determining the time taken to stop and the distance of the ice patch. The subject area includes dynamics and kinematics, focusing on forces and motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations for time and distance, with some verifying the correctness of the time calculated and questioning the distance due to the non-constant velocity of the puck.

Discussion Status

Some participants agree on the correctness of the time calculation, while others express uncertainty about the distance, leading to further exploration of the average velocity concept. There is an ongoing dialogue about the implications of initial and final velocities.

Contextual Notes

Participants note that the velocity is not constant during the puck's deceleration, which affects the calculation of distance. The discussion reflects on the assumptions made regarding average velocity in the context of the problem.

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Homework Statement



A puck of mass 30 g slides across rough ice, experiencing a frictional force of 0.20N. If it was moving at 10km/h when it hit the ice patch,
(a) how much time did it take to stop?
(b) how long was the ice patch?

Given:
m=30g (0.03kg)
Ff=0.20N
V=10km/h (2.7m/s)[/B]

Homework Equations


Fnet=ma
a=v/t
v=d/t[/B]

The Attempt at a Solution



Fnet = ma
a = Fnet/m
a = 0.20N / 0.03kg
a = 6.6m/s2[/B]

a = v/t
t = v/a
t = 2.7m/s / 6.6m/s2
t = 0.40s

v = d/t
d = vt
d = (2.7m/s)(0.40s)
d = 1.08m

So therefore, it took 0.40s for the puck to stop. The ice patch was 1.08m.
 
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Sace Ver said:

Homework Statement



A puck of mass 30 g slides across rough ice, experiencing a frictional force of 0.20N. If it was moving at 10km/h when it hit the ice patch,
(a) how much time did it take to stop?
(b) how long was the ice patch?

Given:
m=30g (0.03kg)
Ff=0.20N
V=10km/h (2.7m/s)[/B]

Homework Equations


Fnet=ma
a=v/t
v=d/t[/B]

The Attempt at a Solution



Fnet = ma
a = Fnet/m
a = 0.20N / 0.03kg
a = 6.6m/s2[/B]

a = v/t
t = v/a
t = 2.7m/s / 6.6m/s2
t = 0.40s

v = d/t
d = vt
d = (2.7m/s)(0.40s)
d = 1.08m

So therefore, it took 0.40s for the puck to stop. The ice patch was 1.08m.
Can someone check it over PLS and thank you!
 
Sace Ver said:

Homework Statement



A puck of mass 30 g slides across rough ice, experiencing a frictional force of 0.20N. If it was moving at 10km/h when it hit the ice patch,
(a) how much time did it take to stop?
(b) how long was the ice patch?

Given:
m=30g (0.03kg)
Ff=0.20N
V=10km/h (2.7m/s)[/B]

Homework Equations


Fnet=ma
a=v/t
v=d/t[/B]

The Attempt at a Solution



Fnet = ma
a = Fnet/m
a = 0.20N / 0.03kg
a = 6.6m/s2[/B]

a = v/t
t = v/a
t = 2.7m/s / 6.6m/s2
t = 0.40s

v = d/t
d = vt
d = (2.7m/s)(0.40s)
d = 1.08m

So therefore, it took 0.40s for the puck to stop. The ice patch was 1.08m.
The time is correct. The distance is not correct.

The velocity is not constant, so the average velocity is not 2.7 m/s.
 
SammyS said:
The time is correct. The distance is not correct.

The velocity is not constant, so the average velocity is not 2.7 m/s.
So would 2.7m/s be the initial velocity and then 0 would be my final velocity?
 
Sace Ver said:
So would 2.7m/s be the initial velocity and then 0 would be my final velocity?
The puck comes to a stop, so yes.
 
SammyS said:
The puck comes to a stop, so yes.
so it'd be d = 2.16?
 
Sace Ver said:
so it'd be d = 2.16?
Yes.
 
SammyS said:
Yes.
THANK U!
 

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