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Finding time and distance with NLM.

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  1. Oct 24, 2015 #1
    1. The problem statement, all variables and given/known data

    A puck of mass 30 g slides across rough ice, experiencing a frictional force of 0.20N. If it was moving at 10km/h when it hit the ice patch,
    (a) how much time did it take to stop?
    (b) how long was the ice patch?

    Given:
    m=30g (0.03kg)
    Ff=0.20N
    V=10km/h (2.7m/s)



    2. Relevant equations
    Fnet=ma
    a=v/t
    v=d/t



    3. The attempt at a solution

    Fnet = ma
    a = Fnet/m
    a = 0.20N / 0.03kg
    a = 6.6m/s2


    a = v/t
    t = v/a
    t = 2.7m/s / 6.6m/s2
    t = 0.40s

    v = d/t
    d = vt
    d = (2.7m/s)(0.40s)
    d = 1.08m

    So therefore, it took 0.40s for the puck to stop. The ice patch was 1.08m.
     
  2. jcsd
  3. Oct 24, 2015 #2
    Can someone check it over PLS and thank you!
     
  4. Oct 24, 2015 #3

    SammyS

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    The time is correct. The distance is not correct.

    The velocity is not constant, so the average velocity is not 2.7 m/s.
     
  5. Oct 24, 2015 #4
    So would 2.7m/s be the initial velocity and then 0 would be my final velocity?
     
  6. Oct 24, 2015 #5

    SammyS

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    The puck comes to a stop, so yes.
     
  7. Oct 24, 2015 #6
    so it'd be d = 2.16?
     
  8. Oct 24, 2015 #7

    SammyS

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    Yes.
     
  9. Oct 24, 2015 #8
    THANK U!!
     
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