Finding Time for a Wave on a Rope

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Homework Help Overview

The problem involves a uniform rope hanging vertically and a disturbance traveling upward through it. Participants are tasked with finding the time taken for the disturbance to reach the top of the rope, given its length and the effects of gravity on wave velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the velocity of the wave at different points along the rope and question the derivation of the wave speed formula. There is an exploration of kinematic equations and their relevance to the problem.

Discussion Status

The discussion is ongoing, with participants questioning assumptions about initial conditions and the applicability of certain equations of motion. Some guidance has been offered regarding the properties of the string that influence wave speed.

Contextual Notes

There are indications of confusion regarding the initial conditions used in the calculations, as well as the relevance of kinematic equations in this context. Participants are also considering the effects of tension and mass distribution in the rope.

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Homework Statement


A uniform rope of mass m hangs vertically from the ceiling, with its lower end free. A disturbance on the rope travels upward from the lower end. Find the time taken by the disturbance to reach the top of the rope if the length of the rope is L.


The Attempt at a Solution



Due to the effect of gravity, velocity of the wave will decrease as it travels up.
v at a distance x from the free end is given by v = [tex]\sqrt{2gx}[/tex]

dt= dx/v
substituting for v and then integrating with limits 0 to t and 0 to L resp we get
t = [tex]\sqrt{2L/g}[/tex]

The answer is t = 2[tex]\sqrt{L/g}[/tex]
 
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Abdul Quadeer said:
v at a distance x from the free end is given by v = [tex]\sqrt{2gx}[/tex]
How did you arrive at this?
 
By using equation of motion v2 - u2 = 2as
I figured out that I used u = 0 which is wrong.
How do we find the velocity then?
 
Abdul Quadeer said:
By using equation of motion v2 - u2 = 2as
I figured out that I used u = 0 which is wrong.
That's a kinematic equation for motion under constant acceleration; not relevant here.
How do we find the velocity then?
What properties of the string determine the speed of a wave?
 
It depends on the elastic and intertial properties of the material of string.
V is given by √(TL/M) where M is the mass of the string and L is its length
At a distance x from the bottom, tension is Mgx/L
Substituting this in equation I got the correct answer.
Thanks a lot!
 

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