Finding Time For Projectile Motion

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Homework Help Overview

The discussion revolves around a projectile motion problem involving a marble launcher that shoots a marble at a specific velocity and angle. Participants are tasked with finding the marble's range, which requires determining the time of flight.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find the time for horizontal motion, with some suggesting the use of vertical motion equations. Others explore trigonometric functions to resolve the initial velocity into horizontal and vertical components.

Discussion Status

The conversation is ongoing, with various approaches being explored. Some participants have provided insights into calculating time based on vertical motion, while others have raised points about the total time of flight considering both ascent and descent.

Contextual Notes

There is an emphasis on the assumption that the projectile lands at the same level from which it was launched, and participants are encouraged to share their work for further assistance.

phhysicssai
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Homework Statement



A marble launcher shoots a marble with a launch velocity of 6.89 m/s @15.0 degrees above horizontal.

-Find the marble's range.



(I tried to do this but I need to be able to find the time for horizontal motion... how would I do that?)

Homework Equations





The Attempt at a Solution

 
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phhysicssai said:

Homework Statement



A marble launcher shoots a marble with a launch velocity of 6.89 m/s @15.0 degrees above horizontal.

-Find the marble's range.



(I tried to do this but I need to be able to find the time for horizontal motion... how would I do that?)

Homework Equations





The Attempt at a Solution


The time is calculated by considering the vertical component of the motion, and treating it like any other vertical motion example.

Or you could have a read of the

http://en.wikipedia.org/wiki/Range_of_a_projectile

then you only need a substitution - provided your projectile is landing at the same level it was launched from and not from/onto a hill/cliff/building.
 
phhysicssai said:

Homework Statement



A marble launcher shoots a marble with a launch velocity of 6.89 m/s @15.0 degrees above horizontal.

-Find the marble's range.



(I tried to do this but I need to be able to find the time for horizontal motion... how would I do that?)

Because its 6.89m/s @ 15.0deg, you can use trigonometric functions to find the initial vertical and horizontal speed:

vertical:
sin(15.0) = o / 6.89

horizontal:
cos(15.0) = a / 6.89

Since the horizontal velocity is constant as gravity does not affect it, the time the projectile is in the air can be found by:

v = a*t

where

v = vertical
a = acceleration due to gravity
t = time of projectile

Once you have the time of the projectile its simple.

We know that distance = velocity * time

-> d = v * t

where d is the "range" we are trying to solve for
where v is the HORIZONTAL velocity
where t is the time of the projectile


Once you have done this, post your work/solution so I can help you further. Nobody here is going to do you homework for you, we can only HELP you if you are trying.
 
jack343, you are forgetting that the projectile goes up AND down so the time of flight is double what you calculate.
 

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