Finding time with force, mass and velocity

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Homework Help Overview

The problem involves calculating the time required for a rocket with a specific thrust to change the velocity of a spacecraft. The context is rooted in physics, particularly in the areas of momentum and impulse.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between impulse and momentum, with some suggesting the use of the impulse-momentum theorem. Questions arise regarding unit conversions and the interpretation of the delta symbol in the equations.

Discussion Status

The discussion is active, with participants exploring different interpretations of the equations involved. Guidance has been offered regarding unit conversions and the application of the impulse-momentum theorem, though no consensus has been reached on the final steps.

Contextual Notes

Participants note the need to convert velocity from cm/s to m/s and to consider the final answer in minutes, as specified in the problem statement.

Ally385
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Homework Statement



Small rockets are used to make tiny adjustments in the speeds of satellites. One such rocket has a thrust of 35 N. If it is fired to change the velocity of a 71700 kg spacecraft by 66 cm/s, how long should it be fired?

Homework Equations



p = mv
Impulse = FΔt

The Attempt at a Solution



Well I think that you might have to find momentum and then plug that into another equation. I'm just not sure what equation that would be since the impulse = FΔt doesn't use momentum.
 
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Ally385 said:
Well I think that you might have to find momentum and then plug that into another equation. I'm just not sure what equation that would be since the impulse = FΔt doesn't use momentum.
Look up the 'impulse-momentum' theorem.

Start here: The Impulse-Momentum Change Theorem
 
So that would make it:

F Δt = Δ p

So that makes that

Δt = Δp/ F
Δt = 4732200 - 0 / 35
Δt = 135205.7

But now how do I get rid of the delta?
 
Ally385 said:
So that would make it:

F Δt = Δ p
Right.

So that makes that

Δt = Δp/ F
Δt = 4732200 - 0 / 35
Δt = 135205.7
Careful with units. Convert the speed to standard units of m/s.

But now how do I get rid of the delta?
Δt is what you are solving for. (You don't need to get rid of the delta; Δt is the time that the thrust must be applied.)
 
So is it in cm/s now because that's what it says in the problem? And then do I have to change it to minutes because that's what it asks for next to the answer blank. (Sorry forgot to put that in.)
 
Ally385 said:
So is it in cm/s now because that's what it says in the problem?
Yes. You need to convert that to m/s.
And then do I have to change it to minutes because that's what it asks for next to the answer blank.
Exactly. The equation will give you the time in standard units of seconds. If you need the answer in minutes, you'll have to convert units.
 
Awesome! Thanks :)
 

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