Finding Torque on current loop.

Click For Summary
The discussion revolves around determining the torque on a current loop situated in the y-z plane within a magnetic field directed along the z-axis. The torque's direction is debated, with one participant suggesting it is into the page due to the right-hand rule, while another believes the torque may be zero since the forces do not induce rotation. The calculation of torque magnitude is hindered by the lack of area information for the loop, which is essential for using the torque formulas provided. It is noted that the size of the loop significantly impacts the torque experienced, similar to the mechanics of a wire loop in an electric motor. Ultimately, understanding the forces on the loop is crucial for accurate torque assessment.
Covenant32
Messages
15
Reaction score
0

Homework Statement


The current loop is in the y-z plane. The direction of the magnetic field is in the z-direction.

A) Which way is the torque on the current loop?
B) If the current is 4 amps and the magnetic field strength is 2.5 Tesla, what is the magnitude of the torque?

here is the picture (which I drew): http://twitpic.com/7e0zv9

Homework Equations



Right Hand Rule 2

T=IAB, T=NIABsinθ. The torque formulas I have necessitate finding an area of the current loop. But, as you can see from the picture (which displays all info. given) there is no way to find the area.


The Attempt at a Solution



A) Well, the loop is parallel to the field. If I use the right hand rule 2, the direction of the torque would be into the page, would it not?

B) I feel that I am missing something crucial. I have done a few problems similar to this one, but I was always given some number to work with to find the area of the current loop.

Seriously, ANY help is very much appreciated. Thank you.
 
Last edited by a moderator:
Physics news on Phys.org
In high school physics, we use F = I*L*B (component of B perpendicular to I).
You could use that the calculate the force on the two sides of the loop that are perpendicular to the B field. If you knew their length. A larger loop would feel a larger force and greater torque than a smaller one. So, same conclusion, the size of the loop is necessary to find the answer.
 
Delphi51 said:
In high school physics, we use F = I*L*B (component of B perpendicular to I).
You could use that the calculate the force on the two sides of the loop that are perpendicular to the B field. If you knew their length. A larger loop would feel a larger force and greater torque than a smaller one. So, same conclusion, the size of the loop is necessary to find the answer.


Thank you, Delphi. I think that perhaps the torque is zero. My reasoning is that the forces acting on the loop are not trying to rotate it. At least that is how it appears.


What do you think of that?
 
No, it is exactly like the loop of wire in an electric motor. The forces are opposite in the top and bottom wires because the current is reversed, so you do have torque about the center of the loop.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
2K
Replies
4
Views
1K
Replies
1
Views
1K
  • · Replies 37 ·
2
Replies
37
Views
4K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
4K