Finding total energy of an oscillator

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SUMMARY

The total energy of a mass-spring oscillator with a mass of 2 kg and a displacement function of x(t) = 2cos(6πt) can be calculated using the formula for maximum speed and kinetic energy. The angular frequency (ω) is determined to be 6π rad/s. The maximum speed (v(max)) is calculated as v(max) = Aω = 2 * 6π = 12π m/s. The total energy (E) is then calculated using the kinetic energy formula KE = 1/2 mv(max)², resulting in a total energy of 144π² J, which approximates to 1420 J, aligning with option B in the provided choices.

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  • Understanding of simple harmonic motion (SHM)
  • Familiarity with kinetic energy calculations
  • Knowledge of angular frequency and its relation to oscillators
  • Ability to manipulate trigonometric functions in physics equations
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  • Explore the relationship between angular frequency and maximum speed in oscillatory systems
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Homework Statement



Find the total energy of the following (mass m= 2 kg) oscillator.

Homework Equations



x=2cos(6∏t)


The Attempt at a Solution



Wouldn't I take my Amplitude of 2 and my period of 6 mulitply them together to get my max velocity of 12 then using KE = 1/2msquared I would take 1/2(2)(12)squared to get 144. But this is no where close to being right. My choice are:

A) 1320
B) 1420
C) 1520
D) 1620
E) 1720
F) 1820
 
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The simple harmonic motion is described with a function x(t)=Acos(ωt), with ω the angular frequency. The maximum speed is v(max)=Aω. You need ω. What is it if x(t)=2cos(6π t)?

ehild
 

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