Finding Uncertainty in Calculating Density p

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To calculate the density p and its uncertainty Δp, the formula p = 6M/(πD^3) is used, but the user is uncertain about how to derive Δp without knowing ΔM and ΔD. The discussion highlights the importance of understanding the resolution of measuring devices to determine uncertainties, suggesting that the resolution can guide the analysis. A proposed method for uncertainty analysis is the Kline and McClintock method, which can help in deriving the uncertainties once the resolutions are known. The user estimates uncertainties based on significant figures, suggesting a zeroth-order uncertainty of 0.00005 kg for mass and 0.0005 m for diameter. This highlights the need for clarity in measuring uncertainties in density calculations.
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Homework Statement


Calculate the density p and its uncertainty \Deltap showing all working

Mass M (kg)
0.0163

\Delta{M} (kg)
?

Diameter D (m)
0.014

\Delta{D} (m)
?

Homework Equations


\rho=MV
p= \frac{6M}{\Pi{D}^3}
Z=\frac{A^2B}{3C^{0.5}}
\frac{\Delta{Z}}{Z}=\frac{2\Delta{A}}{A}+\frac{\Delta{B}}{B}+(1/2)\frac{\Delta{C}}{C}


The Attempt at a Solution


I have tried to use p= \frac{6M}{\Pi{D}^3} but i don't think this is the equation to get the answer.
To find \Delta{p}, I don't understand how i can find \Delta{p} if i do not have \Delta{m} and \Delta{D}(which i don't understand how to get) from the equation:

\frac{\Delta{p}}{p}=\frac{\Delta{m}}{m}+\frac{\Delta{D}}{D}

Hope someone can help me
P.S Paymemoney
 
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You are indeed in a pickle. I've never seen an uncertainty analysis like this.

Do you know the resolution of the measuring devices? The resolution is the "smallest marking
" on your measuring device. For example: Most rulers have 1/16th of an inch as the smallest mark, therefore the resolution would be 1/16th of an inch.

Once you know that, you should be able to preform a uncertainty analysis using the Kline and McClintock method.

An example can be found http://lyle.smu.edu/me/2142/uncert/uncert.htm"

I feel like this will not answer your question because I've never seen a uncertainty method like this.

Taking a compete stab in the dark, and making quite a few assumptions.

I assume that since kg is measured to .0103, that these are all significant digits and that the resolution is .0001 kg. Therefore, the zeroth-order uncertainty is .0001/2 kg = .00005kg.

Similarly for the diameter. .014, all significant. The uncertainty1 is .001 m. The Zeroth-Order uncertainty is .001m/2=.0005m

See Attachment
Uncert.jpg
 
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