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## Homework Statement

We have a lever system. The end of the left side is a distance w1 from the pivot. The end of the right side is a distance w2 from the pivot. When no masses are attatched the lever is touching the ground on the left side. We place a known mass called m1 on the far left side and an unknown mass m2 on the far right side. The system is now in equilibrium. Then we remove the masses and place the mass m2 on the far left side and a know mass m3 on the right side. The system is again in equilibrium. Find an expression for the unknown mass m2 expressed by the known masses m1 and m3.

## Homework Equations

Equation for static equilibrium.

## The Attempt at a Solution

m1g*w1+Mgx=m2g*w2

m2g*w1+Mgx=m3g*w2

M is the mass of the lever and x is the distance the center of mass is from the pivot. Subtracting the frist equation from the 2nd lets me get rid of Mgx but I cant seem to get rid of w1 and w2. The answer is supoused to be m2=sqrt (m1*m3). Ive notice that this is the answer you get if you ignore Mgx from the equations, so what I dont understand is why you can do that. Mgx is generating a torque and I dont understand why you can just say that m1g*w1=m2g*w2 and m2g*w1=m3g*w2

Any help is appreciated