Finding Values of a & b for Differentiability of f(x)

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Homework Help Overview

The discussion revolves around finding the constants a and b for the function f(x) to ensure it is differentiable across the real numbers. The function is defined piecewise, with different expressions for x < 2 and x >= 2.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to equate the two pieces of the function at x = 2 to ensure continuity and differentiability. There are questions about how to solve for the constants a and b given the piecewise nature of the function.

Discussion Status

Some participants have provided hints about checking continuity and differentiability at the point where the function changes, specifically at x = 2. There is an ongoing exploration of how to derive the necessary equations from the conditions of continuity and differentiability.

Contextual Notes

Participants note that there are two unknowns (a and b) and express concern about how to solve for them simultaneously. There is also mention of needing to verify that the slopes of the tangents are the same at the transition point for differentiability.

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Homework Statement


Find the values of the constants a and b such that the function f(x) is differentiable on R


Homework Equations


f(x) = ax2 if x < 2

f(x) = -4(x-3) + b if x >= 2


The Attempt at a Solution


ax2 = -4(x-3) + b
2xa = -4x
a = -2


I believe that I need to equate the equations but with a value of a how do I find b and then prove that it's differentiable?
 
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Welcome to PF!

Hi souldoutt! Welcome to PF! :smile:

(however did you get 2xa = -4x? :confused:)

Hint: the only problem is at x = 2.

So just bung x = 2 in, and check for continuity and differentiability. :smile:
 


I got the 2xa = -4x by differentiating both sides.
But with 2 separate unknown constants, how would i solve for them? I can plug the value x = 2 into the equations but i won't get an answer to confirm whether the second part of the function is actually starting from x = 2.

Then wouldn't I still need to have the constants in order to check whether the slopes of the tangents are the same? (therefore differentiable)?



thanks for the welcome too.
 
souldoutt said:
I got the 2xa = -4x by differentiating both sides.
But with 2 separate unknown constants, how would i solve for them? I can plug the value x = 2 into the equations but i won't get an answer to confirm whether the second part of the function is actually starting from x = 2.

Then wouldn't I still need to have the constants in order to check whether the slopes of the tangents are the same? (therefore differentiable)?

Hi souldoutt! :smile:

For continuity, if you put x = 2, you get f(2) = 4a and = 4 + b,

so your continuity equation is 4a = 4 + b.

And similarly for differentiability you get f'(2) = 4a = -8.

So … ? :smile:
 


souldoutt said:

Homework Statement


Find the values of the constants a and b such that the function f(x) is differentiable on R


Homework Equations


f(x) = ax2 if x < 2

f(x) = -4(x-3) + b if x >= 2


The Attempt at a Solution


ax2 = -4(x-3) + b
2xa = -4x
a = -2
Yes, a must be -2. Now, you put a= -2 and x= 2 in the first equation you have -4= 4+ b. Solve for b.


I believe that I need to equate the equations but with a value of a how do I find b and then prove that it's differentiable?
To prove it is differentiable, with the correct values for a and b, Look at the difference quotient limit.
 


in the first equation you have -4= 4+ b.

It should be -8 instead of -4 right? Because it is ax2 which = -8 when the numbers are plugged in.

Then, once I have the values of a and b the difference quotient limit to check for differentiability is the difference quotient limit of the derivatives correct?
 

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