Finding velocity given change in potential

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SUMMARY

An electron accelerated from rest by a potential difference of 422 V achieves a velocity calculated through energy conservation principles. The initial potential energy is converted into kinetic energy, leading to the equation 422 eV = 0.5mv^2. The correct approach involves converting the potential energy from electronvolts (eV) to joules, resulting in the equation 6.752E-17 J = 0.5mv^2, which yields the accurate velocity of the electron.

PREREQUISITES
  • Understanding of kinetic energy (KE = 0.5mv^2)
  • Knowledge of potential energy in electronvolts (eV)
  • Familiarity with charge of an electron (q)
  • Basic principles of energy conservation
NEXT STEPS
  • Learn about energy conversion between electronvolts and joules
  • Study the concept of electric potential and its effects on charged particles
  • Explore the relationship between charge, potential difference, and energy (U = q * deltaV)
  • Investigate the motion of charged particles in electric fields
USEFUL FOR

Students in physics, particularly those studying electromagnetism and energy conservation, as well as educators seeking to clarify concepts related to electron dynamics and energy transformations.

Xender
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Homework Statement



An electron is accelerated from rest by a potential difference of 422 V. What is its velocity?

Homework Equations



KE = .5mv^2

The Attempt at a Solution



Since the electron started from rest, there is no KE at the start, just potential. After it is accelerated I assumed that there was not potential and that the electron only had potential energy.
Doing this, i was able to set up a conservation of energy equation where:
422 = .5mv^2

is this the correct way of going about solving this?
 
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Your thinking is correct, but you should watch the units carefully. More to the point, what are the energy units that go with 422?
 
eV goes with 422, but KE would be in joules... uh oh! i did some digging and ended up finding that getting the deltaU = q * deltaV (U is change in potential energy, V is change in the potential, q is charge). i multiplied my potential by the charge and then set up the new equation: 6.752E-17 = .5mv^2 and got the right answer. Thanks mate.
 

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