Finding velocity given change in potential

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Xender
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Homework Statement



An electron is accelerated from rest by a potential difference of 422 V. What is its velocity?

Homework Equations



KE = .5mv^2

The Attempt at a Solution



Since the electron started from rest, there is no KE at the start, just potential. After it is accelerated I assumed that there was not potential and that the electron only had potential energy.
Doing this, i was able to set up a conservation of energy equation where:
422 = .5mv^2

is this the correct way of going about solving this?
 
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eV goes with 422, but KE would be in joules... uh oh! i did some digging and ended up finding that getting the deltaU = q * deltaV (U is change in potential energy, V is change in the potential, q is charge). i multiplied my potential by the charge and then set up the new equation: 6.752E-17 = .5mv^2 and got the right answer. Thanks mate.