Finding velocity using given angle

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Homework Help Overview

The problem involves a body projected at a speed of 50 m/s at an angle of 53 degrees with the horizontal, and the objective is to determine the time at which the velocity makes an angle of 33.7 degrees with the horizontal. The context includes concepts from two-dimensional motion and possibly calculus.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the height formula involving sine and gravity but struggles with determining the appropriate initial velocity and time. Some participants suggest breaking down the motion into x and y components and calculating the initial and final speeds for the y component, along with the time required for the change in speed.

Discussion Status

Participants are exploring different approaches to the problem, with some guidance provided on considering the components of motion. One participant reports a specific time of 2 seconds as a potential solution, but there is no explicit consensus on the correctness of this value.

Contextual Notes

The original poster expresses uncertainty about the initial conditions and the time variable, indicating potential constraints in the problem setup.

dahano
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Homework Statement

:
A body is projected with 50m/sec at an angle of 53 degree with the horizontal. After what time velocity makes an angle 33.7 degree with horizontal. (tan 33.7 = 2/3)[/B]

Homework Equations

: Mostly from 2-Dimension and maybe calculus.[/B]

The Attempt at a Solution

: I've first picked up the second part of the question and tried to find out the height at 33.7 degree angle by using h = uSinθt - 1/2gt but in this, I can't decide that what u should I put because 50m/sec is at the ground level. Moreover, I also don't know the time, t. And thus this method can not be used. What could be the other way? Please guide me in layman's term.[/B]
 
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Take into consideration that the motion consists of both x and y components (x=vcosθ and y=vsinθ). Perhaps you could try calculating what the initial speed and final speeds are for the y component. Then try calculating how much time it would take for that change in speed using your other kinematics formulas.
 
Adrian Jimenez said:
Take into consideration that the motion consists of both x and y components (x=vcosθ and y=vsinθ). Perhaps you could try calculating what the initial speed and final speeds are for the y component. Then try calculating how much time it would take for that change in speed using your other kinematics formulas.
Yep, that worked! I've got 2 seconds as the answer and hopefully it must be correct. Thanks :-)
 
dahano said:
Yep, that worked! I've got 2 seconds as the answer and hopefully it must be correct. Thanks :-)
I confirm 2 sec. (More precisely, 2.03, using 9.8 for g.)
 

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