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v=d/t

I have no idea how to even approach this question. How do I apply formulas to solve this question given only the height of the football??

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- Thread starter akb16
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- #1

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v=d/t

I have no idea how to even approach this question. How do I apply formulas to solve this question given only the height of the football??

- #2

Doc Al

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- #3

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- #4

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I have no idea how to even approach this question.

Either do I, with the information you're given.

Since footballs are generally not kicked straight up, they follow a parabolic path. Without knowing the horizontal distance from the point where it was kicked to the point where it reached it's peak height, you cannot come up with a definitive answer.

- #5

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A football is kicked from a height of 2.0m

Wow! The kicker must be a giant!

- #6

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s=ut+0.5at^2

v^2 - u^2 = 2as

remember to only use the part of the ball's motion from the start t=0s to the time at which it reaches it's max hieght....

another thing that we will have to assume constant verticle acceleration for this question (which in practise is not)

- #7

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- #8

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assuming the ball is thrown vertically upwards and neglecting air resistance, it can be solved

cheers

- #9

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thus the initial velocity would be having two components (one in the x direction the other in the y direction) and the y component will be

u*Sin(k)

- #10

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Like I said before, you need more information in order to solve the problem; like angle or distance kicked. Or, perhaps, the football's velocity as it hit the ground (which will differ from the initial velocity since it was kicked from a height of 2 meters!).

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