Finding voltage change for current change for diode

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SUMMARY

The discussion focuses on calculating the change in voltage across a diode when the current changes from 0.1 mA to 10 mA, resulting in a voltage change of approximately 115.1 mV. The relevant equation used is V2 - V1 = VT ln(I1/I2), where VT is the thermal voltage, typically around 25.85 mV at room temperature. The initial voltage, V1, is assumed to be 0.7 V for calculation purposes. Participants confirm that the change in voltage is the primary concern, not the final voltage value.

PREREQUISITES
  • Understanding of the diode equation: i = Ise^(V/VT)
  • Knowledge of thermal voltage (VT) and its value at room temperature (approximately 25.85 mV)
  • Familiarity with logarithmic functions and their application in electrical engineering
  • Basic concepts of current and voltage relationships in semiconductor devices
NEXT STEPS
  • Research the diode equation and its parameters, including saturation current (I_s)
  • Learn about the thermal voltage (VT) and its dependence on temperature
  • Explore the physical characteristics of diodes that affect their performance
  • Study practical applications of diode voltage/current relationships in circuit design
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in semiconductor device analysis will benefit from this discussion.

bl965
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Homework Statement


Find the change in diode voltage if the current changes from 0.1 mA to 10 mA. Ans. 120 mV

Homework Equations


V2-V1=VTln(I1/I2)

The Attempt at a Solution


That is all the information given. The only equation I can think to use is the diode voltage/current relationship, but a value for initial voltage is not given. The calculation assuming V1=0.7 V V2=0.025ln(10/0.1)+0.7 = 0.8151.

Thanks for the help.
 
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bl965 said:

Homework Statement


Find the change in diode voltage if the current changes from 0.1 mA to 10 mA. Ans. 120 mV

Homework Equations


V2-V1=VTln(I1/I2)

The Attempt at a Solution


That is all the information given. The only equation I can think to use is the diode voltage/current relationship, but a value for initial voltage is not given. The calculation assuming V1=0.7 V V2=0.025ln(10/0.1)+0.7 = 0.8151.

Thanks for the help.
But the problem statement only asks for the change in voltage, not the final voltage...
 
berkeman said:
But the problem statement only asks for the change in voltage, not the final voltage...
The only other equation in the section is i = IseV/VT. How would I find change in voltage?
 
What is the diode equation?
 
berkeman said:
What is the diode equation?
i = IseV/VT is the only equation and Is is not given.
 
bl965 said:
i = IseV/VT is the only equation and Is is not given.
I_s is a constant...
 
berkeman said:
I_s is a constant...
From what i researched it depends on the diodes physical characteristics. The information above is all that is provided. I could not find a constant value for Is.
 
bl965 said:
From what i researched it depends on the diodes physical characteristics. The information above is all that is provided. I could not find a constant value for Is.
Just assume it is the same for the test diode for the two test currents. Can you write the two equations and solve them to get the delta-V?
 
V2-V1=VTln(I1/I2) = 0.025 ln (10/0.1) = 115.1 mV ?
 
  • #10
bl965 said:
V2-V1=VTln(I1/I2) = 0.025 ln (10/0.1) = 115.1 mV ?
Looks good. The only thing I would change would be to use 25.85mV for Vt (at room temperature). :smile:
 

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