Finding voltage change for current change for diode

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bl965
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Homework Statement


Find the change in diode voltage if the current changes from 0.1 mA to 10 mA. Ans. 120 mV

Homework Equations


V2-V1=VTln(I1/I2)

The Attempt at a Solution


That is all the information given. The only equation I can think to use is the diode voltage/current relationship, but a value for initial voltage is not given. The calculation assuming V1=0.7 V V2=0.025ln(10/0.1)+0.7 = 0.8151.

Thanks for the help.
 
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bl965 said:

Homework Statement


Find the change in diode voltage if the current changes from 0.1 mA to 10 mA. Ans. 120 mV

Homework Equations


V2-V1=VTln(I1/I2)

The Attempt at a Solution


That is all the information given. The only equation I can think to use is the diode voltage/current relationship, but a value for initial voltage is not given. The calculation assuming V1=0.7 V V2=0.025ln(10/0.1)+0.7 = 0.8151.

Thanks for the help.
But the problem statement only asks for the change in voltage, not the final voltage...
 
berkeman said:
But the problem statement only asks for the change in voltage, not the final voltage...
The only other equation in the section is i = IseV/VT. How would I find change in voltage?
 
berkeman said:
What is the diode equation?
i = IseV/VT is the only equation and Is is not given.
 
bl965 said:
i = IseV/VT is the only equation and Is is not given.
I_s is a constant...
 
berkeman said:
I_s is a constant...
From what i researched it depends on the diodes physical characteristics. The information above is all that is provided. I could not find a constant value for Is.
 
bl965 said:
From what i researched it depends on the diodes physical characteristics. The information above is all that is provided. I could not find a constant value for Is.
Just assume it is the same for the test diode for the two test currents. Can you write the two equations and solve them to get the delta-V?
 
V2-V1=VTln(I1/I2) = 0.025 ln (10/0.1) = 115.1 mV ?
 
bl965 said:
V2-V1=VTln(I1/I2) = 0.025 ln (10/0.1) = 115.1 mV ?
Looks good. The only thing I would change would be to use 25.85mV for Vt (at room temperature). :smile: