- #1

- 327

- 1

bounded by the graph of x = e^(−y^2) and the y-axis between y=0 and y=1, about the x-axis.

Not sure how to set up the problem

- Thread starter tnutty
- Start date

- #1

- 327

- 1

bounded by the graph of x = e^(−y^2) and the y-axis between y=0 and y=1, about the x-axis.

Not sure how to set up the problem

- #2

- 392

- 0

Shells look easier than discs. Do you know shells?

- #3

- 327

- 1

Yes. 2*pi*r*f(x) dx

- #4

- 392

- 0

In this case, the shells are "sideways" so it's 2*pi*r*f(y) dy. And the r is y.

- #5

- 327

- 1

then let y = e^(-y^2)

ln(y) = ln( e^(-y^2))

ln(y) = -x^2

-sqrt( ln(y) ) = x

- ln(y)^.5 = x

so its

V = 2*pi*y*-ln(y^.5)

1

INT [V]

0

?????

- #6

- 392

- 0

No solving for anything required. This is a very quick problem.

- #7

- 327

- 1

2pi*y*f(y)

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