Kirchoff's Voltage Law - Sum of voltages = 0
Kirchoff's Current Law - Net Sum of Currents going into a node = 0
V = IR
The Attempt at a Solution
I am not sure if I am doing this correctly, could someone please check my work?
Sum of I net at node B = - I2 - 8A + 5A = 0
I2= -3A (3A but in the opposite direction from the arrow drawn)
Sum of VABFH = -(5Ω*I2) - V1 = 0
-5Ω*-3A - V1 = 0
V1= 15 V
Sum of VDEFG= -(I3*5Ω) + 50V - V1 = 0
-5*I3 + 50V - 15V = 0
I3 = 7A
I am particularly concerned if I am treating the ampmeter or voltage meter right (Do I need to account for their inside resistance?) and whether or not I am using the correct signs.
Thank you for your help.
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