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Finding weight of a beam using torque & equilibrium?

  1. Apr 25, 2016 #1
    1. The problem statement, all variables and given/known data
    A uniform beam at equilibrium is suspended by a cord at X which is 2m from one end of the beam and and 3m from the other end. There is a mass of 28N attached to the 2m end and a mass of 10N on the 3m end. Determine the weight force of the beam

    2. Relevant equations
    Tclockwise=Tanticlockwise. T=Fd.



    3. The attempt at a solution
    (28×2)+2.5F=10×3
    56+2.5F=30
    2.5F=-26
    F=-10.4N
    The actual answer is 52N
     
  2. jcsd
  3. Apr 25, 2016 #2

    TSny

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    Homework Helper
    Gold Member

    Welcome to PF!

    Be sure you are clear on which point you are choosing as the origin for calculating the torques. The torques for each force must be determined using the same origin.
     
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