Finding weight of a beam using torque & equilibrium?

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Homework Help Overview

The discussion revolves around a problem involving a uniform beam in equilibrium, suspended by a cord with weights attached at both ends. Participants are tasked with determining the weight force of the beam using principles of torque and equilibrium.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of torques and the choice of origin for torque calculations. There are attempts to clarify the setup and the reasoning behind specific values used in the equations.

Discussion Status

Some participants have provided guidance on the importance of consistent torque calculations, while others are seeking clarification on specific components of the problem. Multiple interpretations of the setup are being explored, and there is an ongoing inquiry into the correct approach to arrive at the desired weight force.

Contextual Notes

There are repeated references to the same problem statement and attempts, indicating a focus on understanding the reasoning rather than simply arriving at a solution. The discussion includes a note about the need for participants to show their work for further guidance.

chmergatroyd
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Homework Statement


A uniform beam at equilibrium is suspended by a cord at X which is 2m from one end of the beam and and 3m from the other end. There is a mass of 28N attached to the 2m end and a mass of 10N on the 3m end. Determine the weight force of the beam

Homework Equations


Tclockwise=Tanticlockwise. T=Fd.[/B]

The Attempt at a Solution


(28×2)+2.5F=10×3
56+2.5F=30
2.5F=-26
F=-10.4N
The actual answer is 52N[/B]
 
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Welcome to PF!

Be sure you are clear on which point you are choosing as the origin for calculating the torques. The torques for each force must be determined using the same origin.
 
chmergatroyd said:

Homework Statement


A uniform beam at equilibrium is suspended by a cord at X which is 2m from one end of the beam and and 3m from the other end. There is a mass of 28N attached to the 2m end and a mass of 10N on the 3m end. Determine the weight force of the beam

Homework Equations


Tclockwise=Tanticlockwise. T=Fd.[/B]

The Attempt at a Solution


(28×2)+2.5F=10×3
56+2.5F=30
2.5F=-26
F=-10.4N
The actual answer is 52N[/B
 
T
Thanks I just confirmed it and it turns out to be correct. 🙏🏿
 
chmergatroyd said:

Homework Statement


A uniform beam at equilibrium is suspended by a cord at X which is 2m from one end of the beam and and 3m from the other end. There is a mass of 28N attached to the 2m end and a mass of 10N on the 3m end. Determine the weight force of the beam

Homework Equations


Tclockwise=Tanticlockwise. T=Fd.[/B]

The Attempt at a Solution


(28×2)+2.5F=10×3
56+2.5F=30
2.5F=-26
F=-10.4N
The actual answer is 52N[/B]
How will I get 52N
 
got said:
How will I get 52N
Please post your attempt so that we can guide you.
 
chmergatroyd said:
(28×2)+2.5F=10×3
Where does the 2.5 come from?
 
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got said:
How will I get 52N
You are replying to a 7 year old thread. If you have a new question or want to discuss the old problem, please start a new thread and show your work. Thank you. This old thread is now closed.
 

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