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Finding weight with force and theta

  1. Oct 5, 2009 #1
    1. The problem statement, all variables and given/known data
    What must W be when the force directed along the leg is 26.0N
    http://session.masteringphysics.com/problemAsset/1012378/6/image5.42.jpg

    2. Relevant equations
    [tex]\Sigma[/tex]F=ma=mg


    3. The attempt at a solution
    I used the two angles and drew the y axis down from the top downward segment to form "two" right triangles. I considered downward on the y axis to be positive. And finally combined the two angles(70) and took 26sin(70)= 24.4N

    Any suggestions would be greatly appreciated.
     
  2. jcsd
  3. Oct 5, 2009 #2

    rl.bhat

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    Homework Helper

    Your calculation is wrong.
    Consider the tension in the two sections of the string be T, which is equal to mg. Resolve these tensions into two components along x and y axis and proceed.
     
  4. Oct 5, 2009 #3
    What are the two strings that I should account for with accompanied tension?
     
  5. Oct 5, 2009 #4

    rl.bhat

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    Homework Helper

    Since string is contentious, tension in all four sections is the same. Here you have to consider the tension in the section of string between two pulleys.
     
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