# Finding weight with force and theta

1. Oct 5, 2009

### k2var2002

1. The problem statement, all variables and given/known data
What must W be when the force directed along the leg is 26.0N
http://session.masteringphysics.com/problemAsset/1012378/6/image5.42.jpg

2. Relevant equations
$$\Sigma$$F=ma=mg

3. The attempt at a solution
I used the two angles and drew the y axis down from the top downward segment to form "two" right triangles. I considered downward on the y axis to be positive. And finally combined the two angles(70) and took 26sin(70)= 24.4N

Any suggestions would be greatly appreciated.

2. Oct 5, 2009

### rl.bhat

Your calculation is wrong.
Consider the tension in the two sections of the string be T, which is equal to mg. Resolve these tensions into two components along x and y axis and proceed.

3. Oct 5, 2009

### k2var2002

What are the two strings that I should account for with accompanied tension?

4. Oct 5, 2009

### rl.bhat

Since string is contentious, tension in all four sections is the same. Here you have to consider the tension in the section of string between two pulleys.