Find the missing force when the boy is pulled

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Homework Help Overview

The problem involves a 15.0 kg boy on a 2.00 kg skateboard being pulled by his parents. The mother exerts a force of 100 N at an angle of 35 degrees, and the system accelerates along the x-axis at 8.50 m/s². The questions posed include finding the father's force magnitude and direction, as well as the distance traveled in a given time.

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Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the forces acting on the boy and skateboard. There are attempts to establish equations based on Newton's laws, with some questioning the assumptions about the direction of forces and the components involved. Others raise concerns about the interpretation of angles and the relevance of vertical forces.

Discussion Status

The discussion is ongoing, with various interpretations of the problem being explored. Some participants suggest focusing on the horizontal components of the forces, while others emphasize the need to consider vertical forces. There is no explicit consensus on the correct approach, but several lines of reasoning have been presented.

Contextual Notes

Participants note potential confusion regarding the angles of the forces and the assumption that they act in the horizontal plane. The implications of these assumptions on the normal force and weight are also under discussion.

  • #31
The skateboard as seen from above. It is rolling in the plane of the screen. The two forces are also in the plane of the screen and have no component perpendicular to the screen. The x-axis is horizontal. A picture is worth 210 words.
Skateboard.png


On Edit: In part (b) we are told that they accelerate for 4 s. Starting from rest at an acceleration of 8.5 m/s2, they would reach a speed of 34 m/s or 76 miles per hour! They must be using sports cars to pull the kid which constitutes reckless endangerment and child abuse. Don't ry this at home. :smile:
 

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  • #32
Ok, I think I did wrong calculation in post 28. We have $$F_2 \cos(35) + F_1\cos(\theta) = ma$$ and we also have ##F_2\sin(35) = F_1\sin(\theta)##. This together leads to $$\tan(\theta) = \frac{F_2\sin(35)}{ma - F_2 \cos(35)} $$ Plugging ##m = 17## kg and ##a= 8.5\; m/s^2##, we would get ##\theta = 42.5## degrees. And then ##F_1 = F_2\sin(35)/\sin(\theta) = 84.9 N##. I hope this is correct.
 
  • #33
Your answer for part (a) agrees with mine.
 
  • #34
IssacNewton said:
But the problem is really confusing. It should explicitly tell the student what the question is talking about.
My view is that the problem is well formulated (it is a VERY common type of introductory mechanics problem) but you have given it a very weird and unexpected interpretation that is totally different than what just about everyone else would ever give it. When you have encountered a few more of these problems you'll see what I mean.
 
  • #35
phinds said:
My view is that the problem is well formulated (it is a VERY common type of introductory mechanics problem) but you have given it a very weird and unexpected interpretation that is totally different than what just about everyone else would ever give it. When you have encountered a few more of these problems you'll see what I mean.
My view differs somewhat from yours. I agree that, after seeing several of these problems, one acquires an intuitive understanding of how to interpret them. That's a sign that one has made the transition from novice to expert. However, I think that the formulator of a well crafted problem should look ahead for possible misunderstandings of the wording and include a figure if there is a possibility of misinterpretation by novices. I also think that the given acceleration is totally unrealistic and absurd. Numerical answers should provide an understanding and an estimating ability of the numbers associated with the quantities that are used. The formulator of this problem apparently did not pay attention to that aspect. For these reasons, I would say that this problem is so-so formulated.
 
  • #36
kuruman said:
For these reasons, I would say that this problem is so-so formulated.
Very reasonable. I didn't even look at the numbers but I have now and I agree w/ you.
 

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