Finding whether a filter is low/high/band pass

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SUMMARY

The discussion centers on determining the type of IIR filter defined by the equation yn = xn - yn-2. The Z-transform of the filter is given as H(z) = 1 / (1 + z^2), which translates to the frequency domain as H(w) = 1 / (1 + e^(4πiw)). The amplitude response is calculated, revealing consistent values of 1/2 across the specified frequency domain w = [0,1]. The conclusion reached is that the filter is a band pass filter, despite initial expectations of zeroes at both ends and a non-zero value in the middle.

PREREQUISITES
  • Understanding of IIR filter design and characteristics
  • Familiarity with Z-transforms and their applications in signal processing
  • Knowledge of amplitude response calculations in the frequency domain
  • Experience with initial and final value theorems in control theory
NEXT STEPS
  • Study the properties of band pass filters in signal processing
  • Learn about the application of Z-transforms in digital filter design
  • Explore the derivation and implications of amplitude response in IIR filters
  • Investigate the initial and final value theorems in more depth
USEFUL FOR

Signal processing engineers, control system designers, and students studying digital filter design will benefit from this discussion.

t.kirschner99
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Homework Statement


Consider the IIR filter yn = xn - yn-2

State whether the filter is low, high, or band pass.

Homework Equations


The Z-transform: $$H(z) = \frac {1} {1+z^2},$$

Subbing ##z = e^{2πiw}## : $$H(w) = \frac {1} {1+e^{4πiw}},$$

Amplitude response: $$|H(w)| = \sqrt{{(\frac {1} {1 + cos{(4πw)}})}^2 + {(\frac {1} {sin{(4πw)}})}^2},$$

The Attempt at a Solution


I set up the domain ##w = [0,1]##

##w = 0##

Amplitude response would equal ##\frac {1} {2}##

##w = \frac {1} {2}##

Amplitude response would equal ##\frac {1} {2}##

##w = 1##

Amplitude response would equal ##\frac {1} {2}##

Doesn't this not prove anything? I know the answer is band pass, but I would expect zeroes on both ends and a number greater than zero in the middle.
 
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