Finding Wronskian with Given Initial Conditions for Non-Homogeneous ODE

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SUMMARY

The discussion focuses on calculating the Wronskian W(y1, y2) for the non-homogeneous ordinary differential equation (ODE) y'' + e^x y' + tan(x) = 0, given that W(y1, y2)[0] = 1. The user considers applying Abel's theorem with p(x) = e^x, leading to the expression W(y1, y2)(0) = c e^{\int{- e^t dt}}. The user concludes that the Wronskian at x = 1 is likely e^(e - 1), although they express uncertainty regarding the correctness of this result.

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Homework Statement


Suppose the Wronskian of W(y1, y2) [0] = 1
y1, y2 are solutions to the differential: y'' + e^xy'+ tanx = 0
Find W(y1, y2)[1] ?

The Attempt at a Solution


So I'm thinking of using Abel's theorem, where p(x) = e^x
W(y1, y2)(0) = = c e^{\int{- e^t dt}}
So, 1 = ce^{e^{-t}}
But I'm not too sure what to do now..

I then tried to find out what y1, y2 were so I could just calculate W directly at x = 1.
Since it's not homogeneous (the tanx term) I was thinking of using variations of parameters. But I the e^x term doesn't allow me to find the characteristic equation to find that..
 
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I think the answer of it was e^(e - 1) but I'm not too sure if it's correct
 

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