Finding x,y,z for ∇f Pointing in +z Direction

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Homework Help Overview

The discussion revolves around finding values of x, y, and z such that the gradient of the function f(x,y,z) = x² + y² + z² points in the positive z direction. Participants are exploring the implications of the gradient vector and its components.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to understand what it means for the gradient vector to point in the positive z direction and how to determine the corresponding values of x, y, and z. Questions are raised about the form of the gradient vector and its implications.

Discussion Status

Some participants have provided interpretations of the condition for the gradient vector, suggesting that it should take the form (0, 0, k) for k > 0. There is ongoing exploration of how to find the specific values of x, y, and z that satisfy this condition.

Contextual Notes

There is some uncertainty regarding the interpretation of the problem and the specific requirements for the values of x, y, and z. Participants are clarifying assumptions about the nature of the gradient vector and its components.

chemphys1
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f(x,y,z) = x2 + y2 + z2

which values of x,y,z does ∇f point in the positive z directionok so I know ∇f = i ∂/∂x + j ∂/∂y + k ∂/∂z

which turns out to be

∇f = 2x i + 2y j + 2z k

but how am I finding values so that z points in the positive direction? what does that even mean?
∇f is gradient, could it have specified x direction or y direction, if so what would differ about how to answer the question?

any help/explanation much appreciated
 
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I guess they mean that a vector points in the positive ##z##-direction if it is of the form ##(0,0,k)## for ##k>0##. Does that help?
 
micromass said:
I guess they mean that a vector points in the positive ##z##-direction if it is of the form ##(0,0,k)## for ##k>0##. Does that help?

I don't recognise this kind of question, how would I go about finding this vector?
 
chemphys1 said:
I don't recognise this kind of question, how would I go about finding this vector?

For which ##(x,y,z)## is the gradient ##(2x,2y,2z)## of the form ##(0,0,k)## for ##k>0##.
 
micromass said:
For which ##(x,y,z)## is the gradient ##(2x,2y,2z)## of the form ##(0,0,k)## for ##k>0##.

is it as simple as follows:
x = 0
y= 0
z = any positive integer?
 
Yes.
 
chemphys1 said:
is it as simple as follows:
x = 0
y= 0
z = any positive integer?

Almost. You mean any positive number.
 
Thank you for the help, it really is appreciated!
 

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