1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Finding |<+y|-θ>|^2 in terms of θ

  1. Oct 11, 2014 #1
    1. The problem statement, all variables and given/known data
    Picture 2.jpg
    What is the probability that an electron emerging from the plus channel of the first device will end up in the minus channel of the second device? Express your answer in terms of θ. (Refer to the attached image)

    2. Relevant equations
    This uses the outcome probability rule that says that "In an experiment that determines the value of an observable, the probability of any given result (i.e., the probability that the quanton's state will collapse to that result's eigenvector) is the absolute square of the inner product of the quanton's original state and the result's eigenvector" (From "Six Ideas that Shaped Physics: Unit Q" by Thomas A. Moore pp. 103")

    3. The attempt at a solution

    This is saying that the result will be 50% regardless of θ. This can't be right. Graphing 1/2(sinθ/2-cosθ/2)^2 gives a probability between 0% and 100%, which I would expect, but that's not what I get when I simplify it.

    I suspect I've done something wrong when I've said sin^2(1/2*θ)+cos^2(1/2*θ)=1, but if the values inside sin^2 and cos^2 are the same, why can't I just say sin^2(A)+cos^2(A)=1?

    On a side note: The second part of the question asks what the quanton's spin state vector would be after leaving the second device. I belive I would use the superposition rule to find this out, but I'm not sure. But I can put that in a different thread if I can't figure it out.


    Ok, I think I've found the solution. I was implying that (A-B)^2=A^2+B^2, which was INCORRECT!. I guess the problem is that I need to re-take basic algebra. Here my new attempt: upload_2014-10-12_1-3-55.png
    Last edited: Oct 12, 2014
  2. jcsd
  3. Oct 17, 2014 #2
    Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
  4. Oct 18, 2014 #3


    User Avatar
    Science Advisor
    Gold Member

    Your updated solution looks correct to me, assuming you have constructed the ##\left|-\theta\right>## ket correctly (I can't recall the results well enough to know if you have a minus sign missing or something like that).
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted